Optimal. Leaf size=135 \[ -\frac {2 e}{5 a d (e \sin (c+d x))^{5/2}}+\frac {2 e \cos (c+d x)}{5 a d (e \sin (c+d x))^{5/2}}-\frac {4 \cos (c+d x)}{5 a d e \sqrt {e \sin (c+d x)}}-\frac {4 E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{5 a d e^2 \sqrt {\sin (c+d x)}} \]
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Rubi [A]
time = 0.18, antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 8, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.320, Rules used = {3957, 2918,
2644, 30, 2647, 2716, 2721, 2719} \begin {gather*} -\frac {4 E\left (\left .\frac {1}{2} \left (c+d x-\frac {\pi }{2}\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{5 a d e^2 \sqrt {\sin (c+d x)}}-\frac {2 e}{5 a d (e \sin (c+d x))^{5/2}}+\frac {2 e \cos (c+d x)}{5 a d (e \sin (c+d x))^{5/2}}-\frac {4 \cos (c+d x)}{5 a d e \sqrt {e \sin (c+d x)}} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2644
Rule 2647
Rule 2716
Rule 2719
Rule 2721
Rule 2918
Rule 3957
Rubi steps
\begin {align*} \int \frac {1}{(a+a \sec (c+d x)) (e \sin (c+d x))^{3/2}} \, dx &=-\int \frac {\cos (c+d x)}{(-a-a \cos (c+d x)) (e \sin (c+d x))^{3/2}} \, dx\\ &=\frac {e^2 \int \frac {\cos (c+d x)}{(e \sin (c+d x))^{7/2}} \, dx}{a}-\frac {e^2 \int \frac {\cos ^2(c+d x)}{(e \sin (c+d x))^{7/2}} \, dx}{a}\\ &=\frac {2 e \cos (c+d x)}{5 a d (e \sin (c+d x))^{5/2}}+\frac {2 \int \frac {1}{(e \sin (c+d x))^{3/2}} \, dx}{5 a}+\frac {e \text {Subst}\left (\int \frac {1}{x^{7/2}} \, dx,x,e \sin (c+d x)\right )}{a d}\\ &=-\frac {2 e}{5 a d (e \sin (c+d x))^{5/2}}+\frac {2 e \cos (c+d x)}{5 a d (e \sin (c+d x))^{5/2}}-\frac {4 \cos (c+d x)}{5 a d e \sqrt {e \sin (c+d x)}}-\frac {2 \int \sqrt {e \sin (c+d x)} \, dx}{5 a e^2}\\ &=-\frac {2 e}{5 a d (e \sin (c+d x))^{5/2}}+\frac {2 e \cos (c+d x)}{5 a d (e \sin (c+d x))^{5/2}}-\frac {4 \cos (c+d x)}{5 a d e \sqrt {e \sin (c+d x)}}-\frac {\left (2 \sqrt {e \sin (c+d x)}\right ) \int \sqrt {\sin (c+d x)} \, dx}{5 a e^2 \sqrt {\sin (c+d x)}}\\ &=-\frac {2 e}{5 a d (e \sin (c+d x))^{5/2}}+\frac {2 e \cos (c+d x)}{5 a d (e \sin (c+d x))^{5/2}}-\frac {4 \cos (c+d x)}{5 a d e \sqrt {e \sin (c+d x)}}-\frac {4 E\left (\left .\frac {1}{2} \left (c-\frac {\pi }{2}+d x\right )\right |2\right ) \sqrt {e \sin (c+d x)}}{5 a d e^2 \sqrt {\sin (c+d x)}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 0.75, size = 124, normalized size = 0.92 \begin {gather*} \frac {\sec ^2\left (\frac {1}{2} (c+d x)\right ) (\cos (c+d x)+i \sin (c+d x)) \left (-6-9 \cos (c+d x)+2 \sqrt {1-e^{2 i (c+d x)}} (1+\cos (c+d x)) \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};e^{2 i (c+d x)}\right )+3 i \sin (c+d x)\right )}{15 a d e \sqrt {e \sin (c+d x)}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.20, size = 187, normalized size = 1.39
method | result | size |
default | \(\frac {-\frac {2 e}{5 a \left (e \sin \left (d x +c \right )\right )^{\frac {5}{2}}}+\frac {\frac {4 \sqrt {-\sin \left (d x +c \right )+1}\, \sqrt {2 \sin \left (d x +c \right )+2}\, \left (\sin ^{\frac {7}{2}}\left (d x +c \right )\right ) \EllipticE \left (\sqrt {-\sin \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right )}{5}-\frac {2 \sqrt {-\sin \left (d x +c \right )+1}\, \sqrt {2 \sin \left (d x +c \right )+2}\, \left (\sin ^{\frac {7}{2}}\left (d x +c \right )\right ) \EllipticF \left (\sqrt {-\sin \left (d x +c \right )+1}, \frac {\sqrt {2}}{2}\right )}{5}+\frac {4 \left (\sin ^{5}\left (d x +c \right )\right )}{5}-\frac {6 \left (\sin ^{3}\left (d x +c \right )\right )}{5}+\frac {2 \sin \left (d x +c \right )}{5}}{e a \sin \left (d x +c \right )^{3} \cos \left (d x +c \right ) \sqrt {e \sin \left (d x +c \right )}}}{d}\) | \(187\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.62, size = 155, normalized size = 1.15 \begin {gather*} -\frac {2 \, {\left (\sqrt {-i} {\left (i \, \sqrt {2} \cos \left (d x + c\right ) + i \, \sqrt {2}\right )} \sin \left (d x + c\right ) {\rm weierstrassZeta}\left (4, 0, {\rm weierstrassPInverse}\left (4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right )\right ) + \sqrt {i} {\left (-i \, \sqrt {2} \cos \left (d x + c\right ) - i \, \sqrt {2}\right )} \sin \left (d x + c\right ) {\rm weierstrassZeta}\left (4, 0, {\rm weierstrassPInverse}\left (4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right )\right ) + {\left (2 \, \cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1\right )} \sqrt {\sin \left (d x + c\right )}\right )}}{5 \, {\left (a d \cos \left (d x + c\right ) e^{\frac {3}{2}} + a d e^{\frac {3}{2}}\right )} \sin \left (d x + c\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \frac {\int \frac {1}{\left (e \sin {\left (c + d x \right )}\right )^{\frac {3}{2}} \sec {\left (c + d x \right )} + \left (e \sin {\left (c + d x \right )}\right )^{\frac {3}{2}}}\, dx}{a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\cos \left (c+d\,x\right )}{a\,{\left (e\,\sin \left (c+d\,x\right )\right )}^{3/2}\,\left (\cos \left (c+d\,x\right )+1\right )} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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